The vapour density of a volatile chloride of divalent metal is 59.5 and equivalent mass of metal is

Asked by Anil | 17th May, 2017, 02:36: PM

Expert Answer:

Molecular formula of the compound is MCl2, where M is the divalent cation.

Vapour density (D) = Molecular mass (M) /2

So molar mass of the compound = 2 x 59.5 = 119

Equivalent mass (E) = molar mass (M) / (number of cation x valency)

Number of cation = 1, and valency  of the cation =2

So, E = 119 / (1x2) = 59.5



Answered by Prachi Sawant | 17th May, 2017, 03:11: PM