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CBSE Class 10 Answered

The sum of two digit number and the number obtained by reversing the order of its digit is 99.if the digits differ by 3,find the number?
Asked by FEHMEEDAH NAZNEEN | 30 Aug, 2010, 09:38: PM
answered-by-expert Expert Answer
Let the ten's place be x and units place be y.
so the original number becomes 10x+y
so
 the number obtained by reversing the digits is 10y+x
ATQ
(10x+y)+(10y+x)=99
11x+11y=99
x+y=11....(i)
also
ATQ,
digits differ by 3
so
either x-y=3 or x-y=-3
lets take
x-y=3..(ii)
so , solving  (i) and (ii)
2x=14
so
x=7
and y=4
so original number is 74
next
 lets take x-y=-3..(iii)
so,
solving (i) and (iii)
2x=8
so x=4
and
y=7
so the number is 47
Answered by | 31 Aug, 2010, 08:59: AM

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