# CBSE Class 10 Answered

**hi**

Asked by chaudahryanshika | 03 Jan, 2023, 10:04: AM

Expert Answer

Question (5)

Quadratic equation :- a x

^{2}+ b x + c = 0for real roots , b

^{2}= ( 4 a c )Given quadratic equation :- x

^{2}+ 4x + k= 0a =1 , b = 4 , c = 1

b

^{2}= 164 ac = 4 k = 16

Hence k = 4

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Question (6)

As shown in figure , we gwt the sides of triangle as 4 unit, 3 unit and 5 unit.

Hence perimeter = 12 unit

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Question (7)

In a given similar triangles ABC and DEF

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Question (8) Partially hidden, unable to answer

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Question (9)

because

ΔOAB is isoceless because OA = OB

Hence

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Question (10)

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Question (11)

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Question (12)

cos1

^{o }cos2^{o}cos3^{o}..........................cos88^{o }cos89^{o}cos90^{o}= 0because cos90 = 0 and ita ppears in product

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Question (13)

let r be the radius of circle. perimeter is ( 2r )

If perimeter of square is ( 2r ) then side of square ( 2r )/4 = ( r )/2

Area of circle : area of square = r

^{2}: (1/4)^{2}r^{2}Let us use = 22/7 , then if simplify above ratio , we get areas are in the ratio 14 : 11

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Question (14)

area of circle is proportioanl to square of radius.

If radii of circle are in the ratio 4:3 , then areas are in the ratio 16:9

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Question (15)

Total surface area of solid hemisphere = 3r

^{2}= 3×49 = 147 cm^{2}-------------------------------------

Question 16

Modal class is between 15 to 20 , because frequency is highest for this class.

Upper limit is 20

Answered by Thiyagarajan K | 03 Jan, 2023, 02:26: PM

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