CBSE Class 10 Answered
hi
Asked by chaudahryanshika | 03 Jan, 2023, 10:04: AM
Expert Answer
Question (5)
Quadratic equation :- a x2 + b x + c = 0
for real roots , b2 = ( 4 a c )
Given quadratic equation :- x2 + 4x + k= 0
a =1 , b = 4 , c = 1
b2 = 16
4 ac = 4 k = 16
Hence k = 4
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Question (6)
As shown in figure , we gwt the sides of triangle as 4 unit, 3 unit and 5 unit.
Hence perimeter = 12 unit
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Question (7)
In a given similar triangles ABC and DEF
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Question (8) Partially hidden, unable to answer
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Question (9)
because
ΔOAB is isoceless because OA = OB
Hence
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Question (10)
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Question (11)
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Question (12)
cos1o cos2o cos3o ..........................cos88o cos89o cos90o = 0
because cos90 = 0 and ita ppears in product
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Question (13)
let r be the radius of circle. perimeter is ( 2r )
If perimeter of square is ( 2r ) then side of square ( 2r )/4 = ( r )/2
Area of circle : area of square = r2 : (1/4) 2 r2
Let us use = 22/7 , then if simplify above ratio , we get areas are in the ratio 14 : 11
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Question (14)
area of circle is proportioanl to square of radius.
If radii of circle are in the ratio 4:3 , then areas are in the ratio 16:9
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Question (15)
Total surface area of solid hemisphere = 3r2 = 3×49 = 147 cm2
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Question 16
Modal class is between 15 to 20 , because frequency is highest for this class.
Upper limit is 20
Answered by Thiyagarajan K | 03 Jan, 2023, 02:26: PM
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