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CBSE Class 10 Answered

hi
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Asked by chaudahryanshika | 03 Jan, 2023, 10:04: AM
answered-by-expert Expert Answer
Question (5)
 
Quadratic equation :- a x2 + b x + c = 0
 
for real roots , b2 = ( 4 a c  )
 
Given quadratic equation :- x2 + 4x + k= 0
 
a =1 , b = 4 , c = 1
 
b2 = 16
 
4 ac = 4 k = 16 
 
Hence k = 4
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Question (6)
 
As shown in figure , we gwt the sides of triangle as 4 unit, 3 unit and 5 unit.
 
Hence perimeter = 12 unit
 
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Question (7)

 
In a given similar triangles ABC and DEF
 
begin mathsize 14px style fraction numerator A B over denominator D E end fraction equals fraction numerator B C over denominator F D end fraction space space space space t h e n space angle B space equals space angle D end style
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Question (8) Partially hidden, unable to answer
 
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Question (9)
 
begin mathsize 14px style angle A O B space equals space 130 degree end style  because begin mathsize 14px style angle P A O space equals space angle P B O space equals space 90 degree end style
ΔOAB is isoceless because OA = OB
 
Hence begin mathsize 14px style angle O A B space equals space angle O B A space equals space 25 degree end style
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Question (10)
begin mathsize 14px style s e c space A space equals space fraction numerator 1 over denominator cos space A end fraction space equals space fraction numerator 1 over denominator square root of 1 space minus space sin squared A end root end fraction space equals space fraction numerator 1 over denominator square root of 1 space minus space open parentheses begin display style 1 half end style close parentheses squared end root end fraction space equals space fraction numerator 2 over denominator square root of 3 end fraction end style
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Question (11)
 
begin mathsize 14px style square root of 3 space cos squared A space plus space square root of 3 space sin squared A space equals space square root of 3 space open parentheses cos squared A plus sin squared A close parentheses equals space square root of 3 end style
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Question (12)
 
cos1o cos2o cos3o ..........................cos88o cos89o cos90o = 0
 
because cos90 = 0 and ita ppears in product
 
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Question (13)
 
let r be the radius of circle. perimeter is ( 2begin mathsize 14px style pi end styler )
 
If perimeter of square is ( 2begin mathsize 14px style pi end styler ) then side of square ( 2begin mathsize 14px style pi end styler )/4 = ( begin mathsize 14px style pi end styler )/2
 
Area of circle : area of square = begin mathsize 14px style pi end styler2  : (1/4) begin mathsize 14px style pi end style2 r2
 
Let us use begin mathsize 14px style pi end style = 22/7 , then if simplify above ratio , we get areas are in the ratio 14 : 11
 
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Question (14)
 
area of circle is proportioanl to square of radius.
 
If radii of circle are in the ratio 4:3 , then areas are in the ratio 16:9
 
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Question (15)
 
Total surface area of solid hemisphere = 3begin mathsize 14px style pi end styler2 = 3begin mathsize 14px style pi end style×49 = 147begin mathsize 14px style pi end style cm2
 
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Question 16
 
Modal class is between 15 to 20 , because frequency is highest for this class.
 
Upper limit is 20
Answered by Thiyagarajan K | 03 Jan, 2023, 14:26: PM

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hi
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