The sum of the digits of a two digit number is 12 . The number obtained by interchanging Its digits exceed the given number by 18 find the number
Asked by sunandkumar151 | 25th Aug, 2020, 08:46: PM
Let the digit at the tens place be x and the digit at the unit place be y.
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
According to the condition, we get
→ y−x=2 ..........(2)
Adding (1) and (2), we get
→ x= 12 - 7 = 5
Hence, the required number is 57.
Answered by Yasmeen Khan | 26th Aug, 2020, 09:28: AM
- 2ax+3by=(a+2b) 3ax+2by=2(a+b)
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