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The sum of the digits of a two digit number is 12 . The number obtained by interchanging Its digits exceed the given number by 18 find the number
Asked by sunandkumar151 | 25 Aug, 2020, 08:46: PM

Let the digit at the tens place be x and the digit at the unit place be y.

x+y=12  .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

According to the condition, we get

(10y+x)−(10x+y)=18

→ 9y−9x=18

→   y−x=2     ..........(2)

Adding (1) and (2), we get

2y=14 y=7

→ x= 12 - 7 = 5

Hence, the required number is 57.

Answered by Yasmeen Khan | 26 Aug, 2020, 09:28: AM

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