the sum of reciprocals of two consecutive numbers is 13/132 find the numbers.

Asked by  | 30th Nov, 2012, 11:19: PM

Expert Answer:

Let the number be X & X+1
1/X+1/(X+1)=13/132
or, taking LCM
 
(X+1+X)/(X^2+X)=13/132
Cross multiplying
132+264X=13X^2+13X
or, 13X^2-251X-132=0
 
this equation does not have ingral roots as the discriminant is not a perfect square ther such a condition is not possible .
 
 
NOTE: If in place of 13/132 it is 23/132 then the numbers will be 12 &13.

Answered by  | 1st Dec, 2012, 12:17: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.