The density of 3 M solutionof NaClis 1.25g/ml. Calculate molality of solution.

Asked by Sandeep | 12th Sep, 2015, 05:36: PM

Expert Answer:

Solution:

Molarity = 3 mol L-1

Mass of NaCl in 1 L solution = 3 x 58.5 =175.5g

Mass of 1 L solution = 1000 x density = 1000 x 1.25 = 1250g

Mass of water in solution = 1250 -175.5 = 1074.5g

Hence, molality(m) = Moles of solute/Mass of solvent in kg = 3/1.0745 = 2.79 m

Answered by Vaibhav Chavan | 12th Sep, 2015, 05:57: PM