CBSE Class 11-science Answered
The density of 3 M solutionof NaClis 1.25g/ml. Calculate molality of solution.
Asked by Sandeep | 12 Sep, 2015, 05:36: PM
Expert Answer
Solution:
Molarity = 3 mol L-1
Mass of NaCl in 1 L solution = 3 x 58.5 =175.5g
Mass of 1 L solution = 1000 x density = 1000 x 1.25 = 1250g
Mass of water in solution = 1250 -175.5 = 1074.5g
Hence, molality(m) = Moles of solute/Mass of solvent in kg = 3/1.0745 = 2.79 m
Answered by Vaibhav Chavan | 12 Sep, 2015, 05:57: PM
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