CBSE Class 11-science Answered
<div>The coefficeint of linear expansion of solid in one direction is 0.03 x <img class="Wirisformula" alt="10 to the power of negative 3 end exponent" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=8cd96f7f69f9283103b299baa830a715.png" align="middle" /> / <img class="Wirisformula" alt="ring operator" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=0e1f2aef7ec4d447d96f71cda147c5a8.png" align="middle" />C and in directions perpendicular to it is 0.02 x <img class="Wirisformula" alt="10 to the power of negative 3 end exponent" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=8cd96f7f69f9283103b299baa830a715.png" align="middle" />/<img class="Wirisformula" alt="ring operator" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=0e1f2aef7ec4d447d96f71cda147c5a8.png" align="middle" />C . Find the coefficient of cubical expansion.</div>
<div>1. 0.07 x <img class="Wirisformula" alt="10 to the power of negative 3 end exponent" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=8cd96f7f69f9283103b299baa830a715.png" align="middle" /></div>
<div>2. 0.05 x <img class="Wirisformula" alt="10 to the power of negative 3 end exponent" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=8cd96f7f69f9283103b299baa830a715.png" align="middle" /></div>
<div>3. 0.08 x <img class="Wirisformula" alt="10 to the power of negative 3 end exponent" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=8cd96f7f69f9283103b299baa830a715.png" align="middle" /></div>
<div>4. 0.01 x <img class="Wirisformula" alt="10 to the power of negative 3 end exponent" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=8cd96f7f69f9283103b299baa830a715.png" align="middle" /></div>
Asked by Mamali Nanda | 19 Jul, 2016, 08:54: PM
Expert Answer
Answered by Romal Bhansali | 20 Jul, 2016, 11:12: AM
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