CBSE Class 10 Answered
Solve :
Asked by shankaranarayanan | 23 Feb, 2011, 09:15: PM
Expert Answer
Dear Student,
Let us take the general form of a quadratic equation:
ax2 + bx + c = 0 [a ≠ 0 ] (1)
If and ß be the roots of the equation (1), then
= and ß =
ax2 + bx + c = 0 [a ≠ 0 ] (1)
If and ß be the roots of the equation (1), then
= and ß =
Now, suppose that a, b and c are real and rational. Then, the nature of the roots and ß of
equation (1) is determinedby the expression (b2 – 4ac) under the radical sign.
Therefore (b2 – 4ac) is known as the Discriminant of equation (1). Referred to this discriminant following conclusions can be drawn about the nature of roots and ß of equation (1):
1. If discriminant is positive (that is, if b2 – 4ac > 0), then the roots and ß of equation (1) are real andunequal.
2. If discriminant is zero (that is, if b2 – 4ac = 0), then the roots and ß of equation (1) are real and equal
3. If discriminant is negative (that is, if b2 – 4ac < 0), then the roots and ß of equation (1) are imaginary and unequal
4. If discriminant is positive and a perfect square then the roots of equation (1) are real, rational and unequal. And if the discriminant is positive but not a perfect square then the roots of equation (1) are real, irrational and unequal.
5. If b2 – 4ac is a perfect square but any one of a or b is irrational then the roots of equation (1) are irrational.
Now, here if c is < 0 it means it is a negative digit then discriminant (b2-4ac) becomes positive. Hence the nature of roots will either follow point (1) or point(4) mentioned above.
Regards
Team Topperlearning
Answered by | 23 Feb, 2011, 07:34: PM
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