NEET Class neet Answered
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Asked by surabhilakhara7299 | 24 Jun, 2021, 01:10: AM
Expert Answer
Vertical component of velocity uy is determined from the folowing equation of motion
v2 = uy2 - ( 2 g h )
where v = 0 is the velocity of ball at maximum height , g is acceleration due to gravity and h is maximum height
Hence we have ,
Time taken to reach maximum height is determined from
v = uy - ( g t ) or t = uy / g = ( 27.72 / 9.8 ) = 2.83 s
Horizontal distance S travelled by the ball is determined from
S = ux × t
where ux is the horizontal component of velocity
ux = S / t = 78.4 /2.83 = 27.72 m/s
Hence projection velocity of ball = u =
Answered by Thiyagarajan K | 24 Jun, 2021, 08:58: AM
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