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A coin is dropped in a lift. It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration, then the ratio of t1 to t2 is nearly:
Asked by sa1033278 | 02 May, 2024, 19:37: PM

Let h is the vertical distance between floor of the lift and the point where the coin is dropped.

When the lift is stationary and time taken by the coin to reach the floor of lift is t1 , then time t1 is given by

............................... (1)

where g is acceleration due to gravity.

When the lift is moving upward with constant acceleration a and time taken by the coin to reach the floor of lift is t2 ,

then time t2 is given by .

Exact ratio is calculated from the above relation by substituting the acceleration value .

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