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Asked by amreshmkumar2007 | 18 Mar, 2024, 00:01: AM
Figure shows the gravitational force ' mg ' acting on the disc when it is rolling on inclined plane without slipping .
Where m is mass of disc and g is acceleration due to gravity.
Weight or gravitational force mg is resolved into two components ,
(i) mg sin30 parallel to surface of inclined plane and
(ii) mg cos30 normal to surface of inclined plane .
Force component ( mg sin30 ) is giving linear acceleration for the centre of mass of disc.
Hence , linear acceleration = force / mass = ( mg sin30 ) / m = g sin30 = (1/2) g
Answered by Thiyagarajan K | 18 Mar, 2024, 07:41: AM
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