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Asked by rkr112744 | 31 Jan, 2024, 11:18: PM

Qn.#15

It is given that two equal fragments of mass m are moving perpendicular to each other with speed v .

Hence by momentum conservation , if the third fragment of mass 3m is moving with speed V  then we have

Hence from above expression, we get ,  V = (√2/3) v

Total kinetic energy E after collision is

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Qn.#16

It is given that two equal fragments of mass m are moving perpendicular to each other with speed v .

Hence by momentum conservation , if the third fragment of mass 2m is moving with speed V  then we have

V = v/√2

Total kinetic energy E is

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Qn.#17

If velocity of water in pipe is v  , then length of water volume coming out of pipe is v  .

If unit length of water volume has mass m , then mass of water volume coming out of pipe is  ( m v )

Rate of kinetic energy = (1/2) ( mv ) v2 = (1/2) m v3

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