Request a call back

trick to find out average velocity
Asked by kulsawran12345 | 10 Mar, 2024, 07:31: PM

Below are the three tricks and the formula which you can use in three type of cases respectively:

Case 1:

If an object travels a distance of d1 in time 't' seconds and after a halt travels a distance of d2 in time 't1' seconds and then after one more halt travels a distance d3 in time 't2' seconds then to find the average velocity the formula will be as follows:

Average velocity is calculated as the total displacement divided by the total time taken.

The displacement is the change in position, which is given by the final position minus the initial position.

So, for the given scenario:

Initial position = 0 (assuming the object starts from rest)

Final position = d1 + d2 + d3

Total displacement = Final position - Initial position = d1 + d2 + d3 - 0 = d1 + d2 + d3

Total time taken = t + t1 + t2

Therefore, the average velocity  vavg is given by:

vavg = (d1 + d2 + d3)/ (t+ t1 + t2)

Now

Case 2:

Suppose, the object travels A km/h for x hours, B km/h for y hour. Then to calculate the average velocity the trick formula to solve it faster is

Case 3:

Suppose, the object travels A km/h for x hours, B km/h for y hour. and C km/h for z hour, then the average velocity in this case will be:

Answered by Shiwani Sawant | 11 Mar, 2024, 12:36: PM
NEET neet - Physics
Asked by sa1033278 | 02 May, 2024, 07:37: PM
NEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
NEET neet - Physics
Asked by pandasubhanit | 07 Apr, 2024, 07:42: AM
NEET neet - Physics
Asked by onemile96 | 30 Mar, 2024, 01:04: PM
NEET neet - Physics
Asked by amreshmkumar2007 | 18 Mar, 2024, 12:01: AM
NEET neet - Physics
Asked by kulsawran12345 | 10 Mar, 2024, 07:31: PM