sir , can you help me sove this electro chemistry question. 1)a current of 5A was passed through a solution of copper sulphate.. calculate the weight of copper deposited at the cathode?

Asked by Bharadwaj.R.S | 3rd Mar, 2011, 12:00: AM

Expert Answer:

w=Zit
  If time is 1 hr
w= 3.29 x10 -4 X 5 X 3600 = 59220 x!0-4 g

Answered by  | 3rd Mar, 2011, 10:53: AM

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