sir , can you help me sove this electro chemistry question. 1)a current of 5A was passed through a solution of copper sulphate.. calculate the weight of copper deposited at the cathode?
Asked by Bharadwaj.R.S
| 3rd Mar, 2011,
12:00: AM
Expert Answer:
w=Zit
If time is 1 hr
w= 3.29 x10 -4 X 5 X 3600 = 59220 x!0-4 g
Answered by
| 3rd Mar, 2011,
10:53: AM
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