CBSE Class 10 Answered
Ratio n proportion
Asked by baidshryans | 29 Jan, 2009, 06:48: PM
Expert Answer
5x-11y=2x+5y dividing both side by y we get 5(x/y) - 11 = 2(x/y) + 5 so solving for (x/y) we get (x/y) = 16 / 3
so for 3x^2+2y^2)/(3x^2-2y^2 divide numenator and denominator by y 2 we get ( 3(x/y) 2 + 2 ) / (3 (x/y) 2 - 2)
so put the value of x/y we get 131 / 125
Answered by | 29 Jan, 2009, 11:41: PM
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