Q1.water in an electric kettle connected to a 220V supply took 5 minutes to reach its boiling point .How long would it have taken if the supply had been of 200V? ans(Rs8.80 )

Asked by kanudha gupta | 19th Feb, 2011, 12:00: AM

Expert Answer:

Dear student,

Power = V2/R


Heat gained = (V2/R) t


(V12/R) t1 = (V22/R) t2 


t2 = (220/200)2 x 5 = 6.05 min




Answered by  | 21st Feb, 2011, 12:59: PM

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