Q1.water in an electric kettle connected to a 220V supply took 5 minutes to reach its boiling point .How long would it have taken if the supply had been of 200V? ans(Rs8.80 )

Asked by kanudha gupta | 19th Feb, 2011, 12:00: AM

Expert Answer:

Dear student,

Power = V2/R

 

Heat gained = (V2/R) t

 

(V12/R) t1 = (V22/R) t2 

 

t2 = (220/200)2 x 5 = 6.05 min

 

 

team
topperlearning.com

Answered by  | 21st Feb, 2011, 12:59: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.