ICSE Class 10 Answered
Q1:Where should an object be placed in front of a convex lens of focal length 0.12 m to obtain a real image of size three times the size of the of the object,on the screen?
Q2:A convex lens forms an inverted image of size same as that of the object which is placed at a distance 60 cm in front of the lens.Find:a.The position of the image and b.The focal length of the lens.
Q3:A concave lens forms an erect image of 1/3rd size of the object which is placed at a distance 30 cm in front of the lens.Find:a.The position of the image and b.The focal length of the lens.
Asked by kaursukhjindersukh | 03 Sep, 2018, 10:38: PM
Expert Answer
Required magnification is 3. Also it is required to get real magnified image using convex lens.
Hence image is inverted and magnification formula is given by,
m = -v/u = 3 or v = -3×u ...............(1)
where m is magnification, v is image-to-lens distance and u is object-to-lens distance.
we have lens equation, (1/v) - (1/u) = 1/f ...............(2)
where f is focal length of lens.
Combining (1) and (2) and substitute f=12 cm, we write, (1/3u) +(1/u) = -1/12 ...........(3)
solving eqn.(3) for u, we get u = -16 cm
Hence if object is placed on the left side of convex lens at a distance 16 cm from lens,
we get 3 times magnified and inverted real image on the right side of convex lens
(Only one question per posting is allowed. Hence only first question is answered)
Answered by Thiyagarajan K | 04 Sep, 2018, 05:48: AM
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