CBSE Class 10 Answered
Q-Use the method of substitution to solve each other of the pair of simultaneous equation 1} 2x-9y=9 and 5x+2t=27
Asked by karanbora625 | 19 Apr, 2020, 13:59: PM
The given linear equations are
2x - 9y = 9 ... (i) and 5x + 2y = 27 ... (ii)
From (ii), we have
![x equals fraction numerator 27 minus 2 y over denominator 5 end fraction
S u b s t i t u t i n g space x space i n space left parenthesis i right parenthesis
rightwards double arrow 2 open parentheses fraction numerator 27 minus 2 y over denominator 5 end fraction close parentheses minus 9 y equals 9
rightwards double arrow 54 minus 4 y minus 45 y equals 45
rightwards double arrow negative 49 y equals 45 minus 54 equals negative 9
rightwards double arrow y equals 9 over 49
rightwards double arrow x equals fraction numerator 27 minus 2 open parentheses begin display style 9 over 49 end style close parentheses over denominator 5 end fraction equals 261 over 49](https://images.topperlearning.com/topper/tinymce/cache/5f95ec097f933948d980624af9e9b1bb.png)
Answered by Renu Varma | 19 Apr, 2020, 18:24: PM
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