Ncert solution ex.3.3 Q.no.1.6

Asked by luckyalvi84509 | 20th Feb, 2021, 04:36: PM

Expert Answer:

fraction numerator 3 x over denominator 2 end fraction minus fraction numerator 5 y over denominator 3 end fraction equals negative 2 rightwards double arrow 9 x minus 10 y equals negative 12
x over 3 plus y over 2 equals 13 over 6 rightwards double arrow 2 x plus 3 y equals 13
N o w space c o n s i d e r i n g space t h e space e q u a t i o n s apostrophe
9 x minus 10 y equals negative 12
2 x plus 3 y equals 13
W i l l space s o l v e space t h e space a b o v e space e q u a t i o n space b y space e l i m i n a t i o n space m e t h o d
18 x minus 20 y equals negative 24
18 x plus 27 y equals 117
O n space s o l v i n g space w e space g e t
y equals 3 space space space space space semicolon space space space x equals 2

Answered by Utkarsh Lokhande | 24th Feb, 2021, 12:27: PM