prove that series combination resistance have maximum and parallel combination resistance have minimum current
Asked by | 23rd Sep, 2012, 08:08: PM
When two res are connected in series:
current in the ckt: Is=V/(r1+r2)........(1)
now R ie (r1+r2)sh always be greater than individual res r1 or r2.
so the current will obviously be lesser in comparison with the situation when single res would have used.
in parallel combination:
eq res: R=r1r2/(r1+r2) so R is less than individual res r1 or r2....so the value of current in paallel will be greater.
and current in the ckt: Ip=V(r1+r2)/r1r2........(2)
so Ip/Is =(r1+r2)2/r1r2 sh always be greater than 1, ie current in parallel is greater than current in series.
Answered by | 24th Sep, 2012, 10:36: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number