Asked by dharaelect | 27th Mar, 2019, 01:58: PM
Two charges of +10 μC and - 10 μC are placed at a distance of 5 mm.
Dipole moment is given as,
p = qd
p = 10 x 10-6 x 5 x 10-3
p = 5 x 10-8 Cm
a) Point P is on axis at a distance of 15 cm from a distance O.
Thus, the electric field at point P is,
b) The point Q is perpendicular to the axis of the dipole which is 15 cm apart from point O.
Thus, the electric field due to a dipole at Q is,
Answered by Shiwani Sawant | 27th Mar, 2019, 03:44: PM
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