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CBSE Class 12-science Answered

CALCULATE ELECTIC FEILD INTENSITY DUE TO DATIPOLE OF LENTH 10 CM HAVING CHARGE 5000MICROCOULUMB AT POINT ON AXIS OF LENTH 20 CM FROM ONE OF THE CHARGE 

 

    

Asked by CHITTIBOMMAPARDHANADH | 06 Sep, 2021, 02:27: PM
Expert Answer
Figure shows the dipole having charge 500 μC separated by a distance 10 cm .
 
Electric field at a point P which is at a distance 20 cm from charge at B is given by
 
begin mathsize 14px style E space equals space K space cross times space q space cross times open parentheses fraction numerator 1 over denominator d subscript A superscript 2 end fraction space minus space fraction numerator 1 over denominator d subscript B superscript 2 end fraction space close parentheses end style
where K = 1/(4πεo ) = 9 × 109 N m2 C-2 is Coulomb's constant  ,   q = 500 μC is magnitude of
each charge of dipole , dA = 0.2 m is the distance from positive charge to the point P
and dB = 0.3 m is the distance from negative charge to point P .
 
begin mathsize 14px style E space equals space 9 space cross times space 10 to the power of 9 space cross times space 500 space cross times space 10 to the power of negative 6 to the power of space end exponent space open parentheses fraction numerator 1 over denominator 0.2 cross times 0.2 end fraction space minus space fraction numerator 1 over denominator 0.3 cross times 0.3 end fraction close parentheses space equals space 6.25 space cross times space 10 to the power of 7 N divided by C end style
Answered by Thiyagarajan K | 06 Sep, 2021, 03:40: PM
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