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CALCULATE ELECTIC FEILD INTENSITY DUE TO DATIPOLE OF LENTH 10 CM HAVING CHARGE 5000MICROCOULUMB AT POINT ON AXIS OF LENTH 20 CM FROM ONE OF THE CHARGE        
Asked by CHITTIBOMMAPARDHANADH | 06 Sep, 2021, 02:27: PM
answered-by-expert Expert Answer
Figure shows the dipole having charge 500 μC separated by a distance 10 cm .
 
Electric field at a point P which is at a distance 20 cm from charge at B is given by
 
begin mathsize 14px style E space equals space K space cross times space q space cross times open parentheses fraction numerator 1 over denominator d subscript A superscript 2 end fraction space minus space fraction numerator 1 over denominator d subscript B superscript 2 end fraction space close parentheses end style
where K = 1/(4πεo ) = 9 × 109 N m2 C-2 is Coulomb's constant  ,   q = 500 μC is magnitude of
each charge of dipole , dA = 0.2 m is the distance from positive charge to the point P
and dB = 0.3 m is the distance from negative charge to point P .
 
begin mathsize 14px style E space equals space 9 space cross times space 10 to the power of 9 space cross times space 500 space cross times space 10 to the power of negative 6 to the power of space end exponent space open parentheses fraction numerator 1 over denominator 0.2 cross times 0.2 end fraction space minus space fraction numerator 1 over denominator 0.3 cross times 0.3 end fraction close parentheses space equals space 6.25 space cross times space 10 to the power of 7 N divided by C end style
Answered by Thiyagarajan K | 06 Sep, 2021, 03:40: PM

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CBSE 12-science - Physics
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