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CBSE Class 12-science Answered

abcd
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Asked by mahantabibhutibhusan261 | 06 Nov, 2023, 09:04: PM
answered-by-expert Expert Answer
Initially the electric dipole is at stable equilibrium position. It means electric dipole is aligned with electric field ,
 
i.e direction of electric dipole is parallel to electric field. Potential energy is minimum at stable equilibrium position.
 
When the electric dipole is rotated to unstable equilibrium position means it is rotated to 180o from equilibrium position.
 
In unstable equilibrium position , direction of electric dipole is anti-parallel to the direction of electric field .
 
Workdone to rotate the electric dipole is equal to the potential energy at unstable equilibrium position.
 
Potential energy U of electric dipole at an agnular position θ from stable equilibrium position is
 
begin mathsize 14px style U space equals space minus space p with rightwards arrow on top space times space E with rightwards arrow on top space equals space p space E space cos theta end style
where p is electric dipole moment andE is electric field intensity .
 
POtential energy at angular position 180o is
 
begin mathsize 14px style U space equals space minus space p space cross times space E space cross times cos 180 space equals space p space cross times space E end style
 
Hence work done W to rotate electric dipole from stable equilibrium position to
unstable equilibrium position is
 
begin mathsize 14px style W space equals space p space cross times space E space equals space 4 space cross times space 10 to the power of negative 9 end exponent space cross times space 3 cross times 10 to the power of 3 to the power of space end exponent space equals space 1.2 space cross times space 10 to the power of 5 space J end style
Answered by Thiyagarajan K | 07 Nov, 2023, 12:13: AM

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