calculate the electric field due to the electric dipole of length 2 cm having charge 4 microcoulomb at an angle of minus 60 degree for the direction of electric dipole moment 1 meter for the center to the dipole
Asked by surajsinghrajput4691
| 16th May, 2022,
12:20: AM
Expert Answer:
Let the dipole is at origin of cartesian coordinate system as shown in figure.
electric field at P is given as
where q is magnitude of individual charge of dipole , r+ is ditsance between positive charge and point P ,
r- is ditsance between negative charge and point Pand εo is permittivity of free space .
distance r+ is determined as follows using cosine rule
where r is distance from origin to point P and 2d is length of dipole
similarly we get
let us substitute values
1/(4πεo ) = 9 × 109 N m2 C-2 , q = 4 × 10-6 C and d =1 cm
E = - ( 9 × 109 × 2 × 4 × 10-6 × 0.01 ) / 13 = -720 N

Let the dipole is at origin of cartesian coordinate system as shown in figure.
electric field at P is given as

where q is magnitude of individual charge of dipole , r+ is ditsance between positive charge and point P ,
r- is ditsance between negative charge and point Pand εo is permittivity of free space .
distance r+ is determined as follows using cosine rule

where r is distance from origin to point P and 2d is length of dipole


similarly we get


let us substitute values
1/(4πεo ) = 9 × 109 N m2 C-2 , q = 4 × 10-6 C and d =1 cm
E = - ( 9 × 109 × 2 × 4 × 10-6 × 0.01 ) / 13 = -720 N
Answered by Thiyagarajan K
| 16th May, 2022,
09:57: AM
Concept Videos
- CALCULATE ELECTIC FEILD INTENSITY DUE TO DATIPOLE OF LENTH 10 CM HAVING CHARGE 5000MICROCOULUMB AT POINT ON AXIS OF LENTH 20 CM FROM ONE OF THE CHARGE
- An electric dipole with dipole moment 4×10-9cm is aligned at 30° with the direction of a uniform electric field of magnitude 5×104N/C. Calculate the magnitude of torque acting on the dipole?
- Two short electic dipoles of moment P and 8P are placed in opposite direction on a line at a distance of 15cm. The electic will be zero at point between the dipoles wose distance from the dipole of moment P is
- Obtain the ratio of Electric field formed by an ideal dipole at points lying on axial and equatorial axis.
- Determine electric field at a point p for two identical dipole placed along x and y axis with dipole moment p and angle 45°
- the electric field at a point on the axial line at a distance of 10cm from the centre of an electric dipole is 3×10³NC·¹ in air while at a diatance of 15cm,the electric field is 2×10³NC·¹ Calculate the length of an electric dipole. 3×10³NC·¹
- An electric dipole moment 4x10^-9 cm is aligned at 30°with the direction of a uniform electric field of magnitude 5x10^4 NC^-1.calculate the magnitude of the torque acting on the dipole?
- Determine electric field at a point p for two identical dipole placed along x and y axis with dipole moment p and angle 45°
- An electric dipole is formed by two particles fixed at the end of a light rod of length L. Mass m and 2m with charge q and - q. The system is placed in such a way that the dipole axis is parallel to a uniform electric field. If the dipole is slightly rotated about its center then show that for small angular displacement it's an shm. And find time period
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change