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calculate the electric field due to the electric dipole of length 2 cm having charge 4 microcoulomb at an angle of minus 60 degree for the direction of electric dipole moment 1 meter for the center to the dipole
Asked by surajsinghrajput4691 | 16 May, 2022, 12:20: AM
Let the dipole is at origin of cartesian coordinate system as shown in figure.

electric field at P is given as

where q is magnitude of individual charge of dipole , r+ is ditsance between positive charge and point P ,
r- is ditsance between negative charge and point Pand εo is permittivity of free space .

distance r+ is determined as follows using cosine rule

where r is distance from origin to point P and 2d is length of dipole

similarly we get

let us substitute values

1/(4πεo ) = 9 × 109 N m2 C-2   , q = 4 × 10-6 C and d =1 cm

E = - ( 9 × 109 × 2 × 4 × 10-6 × 0.01 ) / 13 = -720 N
Answered by Thiyagarajan K | 16 May, 2022, 09:57: AM

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