calculate the electric field due to the electric dipole of length 2 cm having charge 4 microcoulomb at an angle of minus 60 degree for the direction of electric dipole moment 1 meter for the center to the dipole
Asked by surajsinghrajput4691
| 16th May, 2022,
12:20: AM
Expert Answer:
Let the dipole is at origin of cartesian coordinate system as shown in figure.
electric field at P is given as
where q is magnitude of individual charge of dipole , r+ is ditsance between positive charge and point P ,
r- is ditsance between negative charge and point Pand εo is permittivity of free space .
distance r+ is determined as follows using cosine rule
where r is distance from origin to point P and 2d is length of dipole
similarly we get
let us substitute values
1/(4πεo ) = 9 × 109 N m2 C-2 , q = 4 × 10-6 C and d =1 cm
E = - ( 9 × 109 × 2 × 4 × 10-6 × 0.01 ) / 13 = -720 N
Let the dipole is at origin of cartesian coordinate system as shown in figure.
electric field at P is given as
where q is magnitude of individual charge of dipole , r+ is ditsance between positive charge and point P ,
r- is ditsance between negative charge and point Pand εo is permittivity of free space .
distance r+ is determined as follows using cosine rule
where r is distance from origin to point P and 2d is length of dipole
similarly we get
let us substitute values
1/(4πεo ) = 9 × 109 N m2 C-2 , q = 4 × 10-6 C and d =1 cm
E = - ( 9 × 109 × 2 × 4 × 10-6 × 0.01 ) / 13 = -720 N
Answered by Thiyagarajan K
| 16th May, 2022,
09:57: AM
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