CBSE Class 10 Answered
please solve this :
Asked by | 08 Jun, 2008, 10:50: AM
let y1(t) be the height of the candle one so y1(t) = h - (ht) / 6 where h is the initial height of the candle.
similarly y2(t) = h - (ht) / 8
now we have y1(t) = 1/2 y2(t)
on solving this we get t=4hrs and 48 mins.
Answered by | 10 Aug, 2008, 04:54: AM
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