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CBSE Class 10 Answered

Please solve this question 

Asked by vikasg13.hardware | 28 Jun, 2018, 06:03: AM
Expert Answer
Let y = x2 + 5 and y = 7[x]
Minimum value of y in equation y = x2 + 5 is 5.
Minimum value of y = 7[x] is less than zero for negative values of x
Hence, roots are in the first quadrant.
Consider curve for 0 < x < 1
The value of x2 + 5 is greater than 5 and 7[x] is zero.
Similarly you can solve it in the interval (1, 2), (2, 3) ....
you will get 
the sum of the squares for 1 < x < 2 is 2.
The sum of the squares for 4 < x < 5 is 23.
The sum of the squares for 5 < x < 6 is 30.
the sum of the squares for 6 < x < 7 is 37.
The sum of the squares is 92
Answered by Sneha shidid | 06 Jul, 2018, 09:31: AM
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