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NEET Class neet Answered

phy
Asked by anushkagoyal656 | 28 Apr, 2022, 05:18: PM
Expert Answer
Let m be mass of bullet moving with initial speed u.
 
Total initial momentum = m u
 
After penetrating wooden block , let the bullet move with speed v . Due to collision, wooden block moves with speed V just after collision.
 
Final momentum just after collision = ( M V ) + ( m v )
where M is mass of wooden block
 
Since momentum is conserved , we have
 
m u = ( M V ) + ( m v )
 
after simplification , we get ,   v = u - (M/m) V  ..................(1)
 
After collision , centre of mass of wooden block is raised 10 cm upwards
 
Hence by energy conservation , (1/2) M V2 = ( M g h )
 
Hence speed of wooden block just after collision , V = begin mathsize 14px style square root of 2 space g space h end root end style   ..................(2)
 
Using eqn.(2) , we rewrite eqn.(1) as
 
v = u - ( M / m ) begin mathsize 14px style square root of 2 space g space h end root end style
v = 400 - ( 2 /.01 ) begin mathsize 14px style square root of 2 cross times 9.8 cross times 0.1 end root end style
v = 120 m/s
Answered by Thiyagarajan K | 28 Apr, 2022, 05:52: PM
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