NEET Class neet Answered
phy
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Asked by anushkagoyal656 | 28 Apr, 2022, 17:18: PM
Let m be mass of bullet moving with initial speed u.
Total initial momentum = m u
After penetrating wooden block , let the bullet move with speed v . Due to collision, wooden block moves with speed V just after collision.
Final momentum just after collision = ( M V ) + ( m v )
where M is mass of wooden block
Since momentum is conserved , we have
m u = ( M V ) + ( m v )
after simplification , we get , v = u - (M/m) V ..................(1)
After collision , centre of mass of wooden block is raised 10 cm upwards
Hence by energy conservation , (1/2) M V2 = ( M g h )
Hence speed of wooden block just after collision , V =
..................(2)
![begin mathsize 14px style square root of 2 space g space h end root end style](https://images.topperlearning.com/topper/tinymce/cache/3193b1001db78011c57c60036c1eed43.png)
Using eqn.(2) , we rewrite eqn.(1) as
v = u - ( M / m ) ![begin mathsize 14px style square root of 2 space g space h end root end style](https://images.topperlearning.com/topper/tinymce/cache/3193b1001db78011c57c60036c1eed43.png)
![begin mathsize 14px style square root of 2 space g space h end root end style](https://images.topperlearning.com/topper/tinymce/cache/3193b1001db78011c57c60036c1eed43.png)
v = 400 - ( 2 /.01 ) ![begin mathsize 14px style square root of 2 cross times 9.8 cross times 0.1 end root end style](https://images.topperlearning.com/topper/tinymce/cache/e9add34ae722d0194f9ea6b8f63fcfad.png)
![begin mathsize 14px style square root of 2 cross times 9.8 cross times 0.1 end root end style](https://images.topperlearning.com/topper/tinymce/cache/e9add34ae722d0194f9ea6b8f63fcfad.png)
v = 120 m/s
Answered by Thiyagarajan K | 28 Apr, 2022, 17:52: PM
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