NEET Class neet Answered
k
Asked by akp70528438 | 28 Nov, 2021, 10:05: AM
Expert Answer
Figure shows the forces acting on blocks of masses m1 and m2 . Weight m1g is acting downward. Equal reaction force R is acting upward
when the block of mass m1 is moving , friction force μR is acting against the motion.Tension force T is acting along the string.
If we apply Newton's law to the block of mass m1 , we get
T - μ R = T - ( μ m1 g ) = m1 a ...............................(1)
where a is acceleration of system.
f we apply Newton's law to the block of mass m2 , we get
m2 g - T = m2 a ...............................(2)
By adding eqn.(1) and (2) , we get ,
m2 g - ( μ m1 g ) = ( m1 + m2 ) a
Hence acceleration a is given from above expression as
......................................(3)
We get Tension force T fromm eqn.(2) as
T = m2 ( g - a ) .............................(4)
By substituting acceleration a from eqn.(3) , we get tension force T from eqn.94) as
Answered by Thiyagarajan K | 28 Nov, 2021, 12:09: PM
NEET neet - Physics
Asked by sayrapatelsp09 | 04 Dec, 2024, 20:32: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by jhansikethburugu2008 | 04 Oct, 2024, 22:09: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by sahilsalam2006 | 28 Dec, 2023, 09:30: AM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by shrutishrivastava2505 | 04 Dec, 2023, 11:55: AM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by beuradeshraj | 20 Jan, 2023, 10:40: AM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by Lashkkkuer | 28 Sep, 2022, 20:03: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by adititiwari601 | 08 Jun, 2022, 22:49: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by adititiwari601 | 08 Jun, 2022, 22:48: PM
ANSWERED BY EXPERT