NEET Class neet Answered
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Asked by akp70528438 | 28 Nov, 2021, 10:05: AM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/93d11209c8e63489979a4b2e5ce1f62f61a31fd24a2991.50744087f5.png)
Figure shows the forces acting on blocks of masses m1 and m2 . Weight m1g is acting downward. Equal reaction force R is acting upward
when the block of mass m1 is moving , friction force μR is acting against the motion.Tension force T is acting along the string.
If we apply Newton's law to the block of mass m1 , we get
T - μ R = T - ( μ m1 g ) = m1 a ...............................(1)
where a is acceleration of system.
f we apply Newton's law to the block of mass m2 , we get
m2 g - T = m2 a ...............................(2)
By adding eqn.(1) and (2) , we get ,
m2 g - ( μ m1 g ) = ( m1 + m2 ) a
Hence acceleration a is given from above expression as
![begin mathsize 14px style a space equals space fraction numerator open parentheses m subscript 2 space minus space mu space m subscript 1 close parentheses g over denominator left parenthesis space m subscript 1 plus space m subscript 2 right parenthesis end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/bf4b089894104dba8390dd6c0e86bbf5.png)
We get Tension force T fromm eqn.(2) as
T = m2 ( g - a ) .............................(4)
By substituting acceleration a from eqn.(3) , we get tension force T from eqn.94) as
![begin mathsize 14px style T space equals space m subscript 2 space end subscript open parentheses g space minus space fraction numerator left parenthesis m subscript 2 subscript space end subscript space minus space mu space m subscript 1 right parenthesis space g over denominator left parenthesis m subscript 1 subscript space end subscript plus m subscript 2 subscript space end subscript right parenthesis end fraction close parentheses space space equals space fraction numerator m subscript 1 subscript space end subscript m subscript 2 over denominator m subscript 1 subscript space end subscript plus m subscript 2 end fraction space open square brackets left parenthesis 1 plus mu right parenthesis space g close square brackets end style](https://images.topperlearning.com/topper/tinymce/cache/2d2bae2d855238612f0c1cec41a97ee9.png)
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