numerical
Asked by Vishad | 12th May, 2013, 07:57: PM
Expert Answer:
When the current goes in a parallel branch. It is always divided in the inverse ratio of the resistances. More resistance will have less current and vice versa, because the value of voltage is same for all the resistances.
So, I(through 10 ohm)/ I(through 15 ohm) = 15/10 = 3/2
And the total current is 1 Amperes that is the sum of all the 2 currents is 1 amp.
So, I10 + I15 = 1
and I10 / I15 = 3/2
Solving above two equations we get
I10 = 0.6A
and I15 = 0.4A
When the current goes in a parallel branch. It is always divided in the inverse ratio of the resistances. More resistance will have less current and vice versa, because the value of voltage is same for all the resistances.
So, I(through 10 ohm)/ I(through 15 ohm) = 15/10 = 3/2
And the total current is 1 Amperes that is the sum of all the 2 currents is 1 amp.
So, I10 + I15 = 1
and I10 / I15 = 3/2
Solving above two equations we get
I10 = 0.6A
and I15 = 0.4A
Answered by | 12th May, 2013, 08:55: PM
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