CBSE Class 10 Answered
in an electric circuit 3 bulbs of raring 40W,60W,100W are connected in parallel .in which bulb the brightness will br maximum and resistance minimum?
Asked by farzul hazan C.S | 14 Jul, 2013, 06:45: AM
Expert Answer
Since, all the bulbs are usually rated at common voltage, V
Let R1, R2 and R3 be the resistances of the 3 bulbs
P1 = 40 = V^2/R1
R1 = V^2/40
Similarly, R2 = V^2/60
R3 = V^2/100
Hence, the resistance would be minimum for R3.
Also, since the resistors are connected in parallel, their power would be same as the given power wattage.
Hence, 100W bulb will the brightest of the 3.
Answered by | 14 Jul, 2013, 06:13: PM
Application Videos
Concept Videos
CBSE 10 - Physics
Asked by khajannirwan | 27 Feb, 2024, 10:20: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by saanviyadla | 24 Jan, 2024, 07:06: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by kamalaranjanmohantymohanty5 | 06 Jan, 2024, 10:05: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by nandhikasugumar | 05 Oct, 2023, 04:01: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by daniya062008 | 02 Oct, 2023, 08:25: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:28: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:21: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:13: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:11: PM
ANSWERED BY EXPERT