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Asked by | 12th Dec, 2012, 11:05: PM
let x be in ten s place and y in unit place.
so, number = 10x + y
As, 10x + y = 4(x + y) [number is 4 times the sum of digits]
10x + y = 4x + 4y
6x = 3y
y = 2x .... (eqn 1)
and, 10x + y = 2(x * y) [number is twice the product of the digits]
10x + y = 2xy
10x + 2x = 4x2 [substituting value of y in eqn 1)
12x = 4x2
x = 3
y = 2x = 6
So, the number = 10x + y = 30 + 6 = 36
let x be in ten s place and y in unit place.
so, number = 10x + y
As, 10x + y = 4(x + y) [number is 4 times the sum of digits]
10x + y = 4x + 4y
6x = 3y
y = 2x .... (eqn 1)
and, 10x + y = 2(x * y) [number is twice the product of the digits]
10x + y = 2xy
10x + 2x = 4x2 [substituting value of y in eqn 1)
12x = 4x2
x = 3
y = 2x = 6
So, the number = 10x + y = 30 + 6 = 36Answered by | 13th Dec, 2012, 10:35: AM
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