CBSE Class 10 Answered
...........
Asked by Sonal13 | 19 Feb, 2010, 11:45: AM
Expert Answer
let
(a,b), (c,d) , (e,f) be the coordinates of the vertices A,B,C of the triangle ABC.
if the given mid pts are that of AB,BC,CA resply
then
(a+c)/2=3
and
(b+d)/2=1
so a+c=6..(i)
b+d=2..(ii)
simly
taking the other sides and their mid pts
we get,
c+e=10..(iii)
d+f=12...(iv)
and
a+e=-6...(v)
b+f=4..(vi)
solving (i) and (iii) and (v)
a=-5, c=11, e=-1
b=-3, d=5 , f=7
Answered by | 19 Feb, 2010, 12:19: PM
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