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# CBSE Class 10 Answered

how to solve 47x+31y=63 31x+47y=15 short trick
Asked by kuldeepsingh89799 | 31 May, 2021, 04:31: PM
Given equations are

47 x + 31 y = 63  ....................... (1)

31 x + 47 y = 15 .........................(2)

Add and subtract the above equations to get numbers of small magnitudes.

By adding (1) and (2) , we get  , 78 x + 78 y = 78  or x + y = 1  ...........................(3)

By subtracing eqn.(2) from eqn.(1) , we get ,  16 x - 16 y = 48  or  ( x - y ) = 3  ............(4)

Hence by solving eqn.(3) and eqn.(4) , we get , x = 2 , y = -1
Answered by Thiyagarajan K | 20 Sep, 2021, 02:18: PM

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