CBSE Class 10 Answered
how to solve 47x+31y=63
31x+47y=15 short trick
Asked by kuldeepsingh89799 | 31 May, 2021, 04:31: PM
Given equations are
47 x + 31 y = 63 ....................... (1)
31 x + 47 y = 15 .........................(2)
Add and subtract the above equations to get numbers of small magnitudes.
By adding (1) and (2) , we get , 78 x + 78 y = 78 or x + y = 1 ...........................(3)
By subtracing eqn.(2) from eqn.(1) , we get , 16 x - 16 y = 48 or ( x - y ) = 3 ............(4)
Hence by solving eqn.(3) and eqn.(4) , we get , x = 2 , y = -1
Answered by Thiyagarajan K | 20 Sep, 2021, 02:18: PM
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