How does decrease in surface area of branched alcohols decrease vander walls forces?
Asked by Girijeshpandey.rjil
| 23rd Apr, 2018,
07:16: PM
Expert Answer:
Let us understand with an example,
2,2 dimethyl propane is a compact, almost spherical molecule whereas, pentane is long and floppier so will experience more forces between molecules.
In above structures, you can see that n-pentane have larger surface area than 2,2 dimethylpropane, which means the Van der Waal's forces of attraction are more in case of n-pentane than 2,2 dimethyl propane.
Answered by Ramandeep
| 24th Apr, 2018,
10:38: AM
Concept Videos
- Introduction of alcohols
- Please answer iupac names from structures..
- what if i have written bithinol instead of bithional?
- What is the common name of 3-Methylbutoxybenzene? Is it methyl isopropyl ether OR isopropyl ether and please explain that the words like n of n gently and i of iso are considered in alphabetic naming
- why C-O bond in phenols is larger than that of alcohols.
- What is alchol, phenol?
- Please explain the following
- Write the IUPAC name of the following:
- Draw the structure of hex-1-en-3-ol compound.
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change