CBSE Class 10 Answered
how do i solve 4/x+3y=14 and 3/x-4y=23 by elimination method
Asked by vedantpandhare007 | 12 Apr, 2020, 02:45: PM
4/x + 3y=14 and 3/x - 4y=23
Let 1/x = m,
4m + 3y = 14...(1) and 3m - 4y = 23 ... (2)
Multiply (1) by 4 and (2) by 3, we get
16m + 12y = 56 ... (3) and 9m - 12y = 69 .... (3)
Adding (3) and (4), we get
25m = 125
→ m = 5
From (1),
4(5) + 3y = 14
→ 3y = 14 - 20
→ y = -2 and m = 1/x = 5 → x = 1/5
Answered by Yasmeen Khan | 12 Apr, 2020, 03:23: PM
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