Hello mam, please send the answer.

Asked by aarthi9 | 20th Jun, 2011, 02:16: AM

Expert Answer:

Let the distance travelled by the marble in 1 sec is x meter. Then the stone would have travelled (10-x) meter from the point 5 mt above the ground.

For the motion of marble using second equation of motion

h = u t + (1/2) g t2

x = 0 + (1/2) x 10 x 12         (where g = 10 m/s2, t = 1 sec)

x = 5 m

Now for the motion of stone, using second equation of motion

h = u t + (1/2) g t2

where u is the initial speed of the stone.

10 – x = u t + (1/2) g t2

10 – 5 = u x 1 + (1/2) x 10 x 12

u = 10 m/s

 

Answered by  | 21st Jun, 2011, 01:18: PM

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