from the top of a building 39.2m,a ball is thrown vertically upward with a velocity 9.8m/s.find the
Asked by | 23rd Jul, 2009, 02:22: PM
To solve this problem, let us take ground as the reference point and vertically upward direction as positive.
Here, x0 = h = 39.2 m
a = g = -10 m/s2
u = 9.8 m/s2 , t = ?
x = x0 + ut + at2 /2
0 = 39.2 + 9.8 t - 9.8 t2 /2
On solving the above quadratic eqn, we will get the time when the ball will hit the ground .
Answered by | 23rd Jul, 2009, 08:11: PM
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