find the roots of the equation x^2+x-p(p+1)=0,where p is a constant

Asked by  | 10th Mar, 2013, 02:13: PM

Expert Answer:

x2+x-p(p+1)=0

x2+(p+1)x-px-p(p+1)=0

x(x+p+1) -p(x+p+1)=0

(x+p+1)(x-p)=0

x=-p-1, p

Answered by  | 10th Mar, 2013, 03:12: PM

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