CBSE Class 11-science Answered
FIND THE AVERAGE SPEED OF AN OBJECT WHOSE SPEED-TIME GRAPH IS GIVEN BELOW.![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/0ddcddd19133ecc46a40f6eebc4ff67955ba1034d7d148.53991669Photo0052.jpg)
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/0ddcddd19133ecc46a40f6eebc4ff67955ba1034d7d148.53991669Photo0052.jpg)
Asked by swarajtopper | 30 Jul, 2015, 17:23: PM
To calculate the average speed, we need to know the total distance travelled.
![begin mathsize 12px style The space total space distance space travelled space equals space Area space of space ΔABF space plus space Area space of space rectangle space BEFC space plus space Area space of space ΔCFD space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1 half space cross times space BF space cross times space AF space plus space open parentheses BF space cross times space BC close parentheses space plus space 1 half space cross times space CE space cross times space ED space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1 half space cross times 100 space cross times space 20 space plus space open parentheses 100 space cross times space 40 close parentheses space plus space 1 half space cross times 100 space cross times space 20 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1 half space cross times 100 space cross times space 20 space plus space open parentheses 100 space cross times space 40 close parentheses space plus space 1 half space cross times 100 space cross times space 20 rightwards arrow Total space distance space travelled space equals space 6000 space straight m Average space Speed space equals space fraction numerator Total space distance space travelled over denominator Total space time space taken end fraction Average space Speed space equals space fraction numerator 6000 space straight m over denominator 80 space straight s end fraction space equals space 75 space straight m divided by straight s end style](https://images.topperlearning.com/topper/tinymce/cache/5209d6e28077f36783932fae61e94986.png)
Answered by Yashvanti Jain | 15 Dec, 2017, 19:42: PM
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![](http://images.topperlearning.com/topper/questions/2543_image018.jpg)
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