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Asked by subhashreeojha235 | 16 Jul, 2023, 07:37: PM
Description of motion of object that corresponds to position-time graph given in fig(1) is given on righ side.

Let us consider a ball is kickec from point A , ball moves at constan speed on smooth surface and getting reflected from wall.

While backward motion, the ball crosses the initial point that is marked as A' and travel till a trap at B and comes to rest thereafter.

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For the velocity-time graph give in fig.(2) , let us consider the motion of  a ball is thrown vertically upwards with initial speed.

When the ball returns to ground , it is bounced back after imapact with ground .

There is a loss of kinetic energy , hence it moves upwards with less speed and this process repeats.

The discontinuties at times t1 , t2 and t3 correspond to change of direction due bouncing back of the ball after impact.

It is to be noted here velocity-time graph has constant slope because acceleration is constant for the bouncing motion of ball.

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Fig(3) is accekeration-time graph that corresponds to impulse given to an object , i.e., action of force for a short time.
Answered by Thiyagarajan K | 19 Jul, 2023, 11:06: AM

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