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CBSE Class 11-science Answered

Express and solve this situation using graph:
Asked by devanshu_jain | 01 Aug, 2010, 12:05: PM
answered-by-expert Expert Answer
Let speed of each bus = v km/h
The distance between the nearest buses plying on either side = vT km.. (i)
For buses going from town A to B :
Relative speed of bus in the direction of motion of man = (v – 20)
Buses plying in this direction go past the cyclist after every 18 min. Therefore separation
between the buses = (v – 20) × 18
From equation (i),
(v – 20) ×(18/60) = vT ......(ii)
For buses coming from B to A :
The relative velocity of bust with respect to man = (v + 20)
Buses coming from town B past the cyclist after every 6 min therefore
(v + 20) ×(6/60) = vT ......(iii)
Solving equations (ii) and (iii), we get
v = 40 km/h and T =(3/20) h
 
Team,
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Answered by | 02 Aug, 2010, 02:14: PM

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