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CBSE Class 11-science Answered

Emperical formula of a gaseous compound is CH2Cl. 0.12 g of the compound occupies a volume of 37.20cc at 105 degree centigrade and 768mm Hg.Find the molecular formula of the compound.



2500 cc of oxygen was burnt with 600cc of ethane.Calculate the volume of unused oxygen and the volume of Carbon dioxide formed.

Asked by tps.mjmdr | 20 Jun, 2018, 10:10: PM
Expert Answer
Given:
 
Oxygen space space equals space 2500 space cc
Ethane space equals space 600 space cc

Reaction space equation space is colon

space space space space space space space 2 straight C subscript 2 straight H subscript 6 space space plus space space space 7 straight O subscript 2 space space space rightwards arrow space space space 4 CO subscript 2 space space plus space space 6 straight H subscript 2 straight O
space space space space space space space space 2 space vol space space space space space space space space space 7 space vol space space space space space space space space space space 4 space vol space space space space space space space space space space 6 space vol

2 space vol space of space of space straight C subscript 2 straight H subscript 6 space gives space 4 space vol space of space CO subscript 2 space
600 space cc space of space straight C subscript 2 straight H subscript 6 space gives space space 4 over 2 cross times 600 space ccl space of space CO subscript 2 space

therefore space 600 space cc space of space straight C subscript 2 straight H subscript 6 space gives space 1200 space cc space of space CO subscript 2

CO subscript 2 space produced space equals space 1200 space cc


2 space vol space of space of space straight C subscript 2 straight H subscript 6 space gives space 7 space vol space of space straight O subscript 2 space

600 space cc space of space straight C subscript 2 straight H subscript 6 space gives space 7 over 2 space cross times 600 space ol space of space straight O subscript 2 space

therefore space vol space of space straight O subscript 2 space equals space 2100 space cc space of space straight O subscript 2

Volume space of space unused space straight O subscript 2 space equals space 2500 space minus 2100

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 400 space cc
 
The volume of unused oxygen is 400 cc
The volume of Carbon dioxide formed is  1200 cc
Answered by Varsha | 21 Jun, 2018, 11:17: AM

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