Divide 41 into two positive parts such that the difference of their square is 369.

let one of the part be X so the other will be 41-X

 

therfor, X^2-(41-X)^2=369

or, (X+41-X)(X-(41-X))=369

or, 41(2X-41)=369

or,2X-41=369/41=9

or, 2X=9+41=50

or,X=50/2=25

 

therefor the parts are 25 &16