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CBSE Class 10 Answered

Divide 41 into two positive parts such that the difference of their square is 369.
Asked by | 30 Nov, 2012, 11:30: PM
answered-by-expert Expert Answer
let one of the part be X so the other will be 41-X
 
therfor, X^2-(41-X)^2=369
or, (X+41-X)(X-(41-X))=369
or, 41(2X-41)=369
or,2X-41=369/41=9
or, 2X=9+41=50
or,X=50/2=25
 
therefor the parts are 25 &16
Answered by | 30 Nov, 2012, 11:44: PM

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