Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

<p>derive the nernst eqn for daniel cell</p>
Asked by aswathy sreekumar | 13 May, 2014, 08:19: PM
Expert Answer

For Daniel cell,

Zn(s)+Cu2+(aq) <=> Zn2+(aq) + Cu(s)

Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu

In Daniell cell, the electrode potential for any given concentration of Cu2+ and Zn2+ ions, we write

For Cathode:

E(Cu2+/Cu) = E0(Cu2+/Cu) – RT/2F ln(1/[Cu2+(aq)]

For Anode:

E(Zn2+/Zn) = E0(Zn2+/Zn) – RT/2F ln(1/[Zn2+(aq)]

The cell potential, Ecell = E(Cu2+/Cu) - E(Zn2+/Zn)

= E0(Cu2+/Cu) – RT/2F ln(1/[Cu2+(aq)] - E0(Zn2+/Zn) + RT/2F ln(1/[Zn2+(aq)]

= E0(Cu2+/Cu) -E0(Zn2+/Zn)- RT/2F ln(1/[Cu2+(aq)] + RT/2F ln(1/[Zn2+(aq)]

= E0(Cu2+/Cu) -E0(Zn2+/Zn)- RT/2F (ln(1/[Cu2+(aq)]- ln(1/[Zn2+(aq)])

Therefore, Nernst equation for Daniel cell is

Ecell = E0cell - RT/2F ln [Zn2+]/[Cu2+]

Ecell = E?cell − 2.303RT/2F ln [Zn2+]/[Cu2+]

Answered by Prachi Sawant | 14 May, 2014, 10:44: AM

Concept Videos

Multiple Choice Questions Practice Test Subjective Questions Webinar Subjective Questions Pre Board Assessment
Answered Unanswered My Questions My Answers
CBSE 12-science - Chemistry
Q. 6. Calculate the emf of the following cell at 298 K Cr(s)/Cr³+ (0.1M)//Fe²+ (0.01M)/Fe(s) [Given: Eºcell = + 0.30 V]
Asked by amankumar2004112 | 04 May, 2022, 01:12: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Please answer this question.
Asked by Balbir | 02 Oct, 2019, 12:29: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
For what concentration of Ag+ will the EMF of te given cell be zero at 25 C .If the concentration of Cu2+ is 0.1 M. EoAg+ = 0.80v and Eo Cu2+ = 0.34 V
Asked by Jsiajaijiaia | 27 Aug, 2019, 12:23: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Please answer. 
Asked by prakriti12oct | 14 Aug, 2019, 12:46: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Electrochemistry What's 'n' in the equation:           E°(cell) = 0.0591/n log Kc  
Asked by rakeshraghav33 | 19 May, 2018, 03:55: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Predict whether the following redox reaction is feasible under the standard conditions or not.              Sn2+(aq) + Cu(s) →   Sn(s) + Cu2+(aq)
Asked by Topperlearning User | 22 Jun, 2016, 02:42: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Zn(s) | Zn2+(0.01M) || Pb2+(1.OM)|Pb(s) Given: Eo Pb2+/Pb = -0.12V and Eo Zn2+/Zn = -0.76V, what is the cell potential of the cell?
Asked by Topperlearning User | 22 Jun, 2016, 02:41: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Calculate the reduction potential for the following half cell reaction at 298 K.             Ag+(aq) + e- →  Ag(s) Given that   (Ag+) = )0.1M and E° = + 0.80V
Asked by Topperlearning User | 22 Jun, 2016, 02:41: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Calculate EMF of the following cell at 298 K             Ni(s) ½ Ni2+(0.01M) ½½ Ag+(0.1M) ½Ag(s)
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Write the Nernst equation and calculate the emf of the following cell at 298 K.Cu (s) | Cu2+ (0.130 M) || Ag+ (1.00M)| Ag (s) Given: EoCu2+/Cu = 0.34V and EoAg+/Ag = +0.80 V.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt