CBSE Class 11-science Answered
can you please give an explanation to the question described under??
Asked by c08ge72256 | 21 Jan, 2012, 09:22: PM
Expert Answer
For the standing wave on a stretched string fixed at both ends , the possible frequencies are
f=nv/2l , it si given that wire resonates at 440 Hz.
So if you know length of wire and which mode of frequency (n=?) resonates you can find out the value of speed.
If you still not get the answer please go to the concept of standing waves.
Answered by | 24 Jan, 2012, 05:13: PM
Concept Videos
-
Waves
This video explains the formation of standing waves on a string and in an o... -
Waves
This video explains the production of beats, beat frequency and the mathema... -
Waves
This video explains the Doppler effect in sound waves and the apparent chan... -
Waves
This video explains the oscillation of particles in transverse and longitud... -
Waves
This video explains the classification of waves and shows examples and char...
CBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sherry.sharma771 | 08 Feb, 2023, 08:25: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by arjunsah797 | 17 May, 2022, 01:19: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by lakshmiks703 | 17 Apr, 2022, 07:23: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by Umeshlochab80 | 12 May, 2021, 09:24: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by umeshlochab887 | 12 May, 2021, 06:17: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by ks076345 | 22 Mar, 2021, 09:20: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by pb_ckt | 22 May, 2019, 10:19: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by drbharatkaila | 13 Feb, 2019, 07:38: PM
ANSWERED BY EXPERT
