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CBSE Class 11-science Answered

can you please give an explanation to the question described under??
Asked by c08ge72256 | 21 Jan, 2012, 09:22: PM
Expert Answer
For the standing wave on a stretched string fixed at both ends , the possible frequencies are
f=nv/2l , it si given that wire resonates at 440 Hz.
So if you know length of wire and which mode of frequency (n=?) resonates you can find out the value of speed.
If you still not get the answer please go to the concept of standing waves.
Answered by | 24 Jan, 2012, 05:13: PM
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