Calculate the number of atoms of C and O in 72.5g of isopropanol C3H7OH (molar mass=60)

Asked by kpbhake | 12th Nov, 2017, 04:49: PM

Expert Answer:

1 space mole space of space isopropanal space contains space 3 space moles space of space Carbon space and space 1 space mole space of space Oxygen
Molar space mass space of space isopropanol space equals space 60 space straight g
therefore space 60 space straight g space of space isopropanol space contains space 3 space moles space of space carbon space and space 1 space mole space of space Oxygen
therefore 72.5 space straight g space of space isopropanol space will space contain
Moles space of space carbon space equals fraction numerator 72.5 cross times 3 over denominator 60 end fraction
space space space space space space space space space space space space space space space space space space space space space space space equals 3.625
space 3.6 cross times 6.022 cross times 10 to the power of 24 space equals 2.1 cross times 10 to the power of 24 space end exponent a t o m s
Moles space of space Oxygen space equals fraction numerator 72.5 over denominator 60 end fraction
space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1.2
1.2 cross times 6.022 cross times 10 to the power of 24 equals 7.22 cross times 10 to the power of 23 space a t o m s

Answered by Varsha | 12th Nov, 2017, 10:58: PM

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