Calculate the enthalpy change
Asked by | 3rd Mar, 2009, 07:36: PM
Expert Answer:
ΔH = Cp X ΔT
= 75.3 x 1 0 = .753kj ( 100C to 0 0C)
-ΔHfus = -6.03kj
ΔH = Cp X ΔT
= 36.8 X (273 -283)
= -0.368kj ( 0 0C to100C")
Total enthalpy change = -5.645kjmol-1
Answered by | 9th Mar, 2009, 03:36: PM
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