Calculate the enthalpy change

Asked by  | 3rd Mar, 2009, 07:36: PM

Expert Answer:

ΔH = Cp X ΔT

        = 75.3 x 1 0   = .753kj       ( 100C  to  0 0C)

-ΔHfus  = -6.03kj

 ΔH = Cp X ΔT

         = 36.8 X (273 -283)

     = -0.368kj       (  0 0C to100C")

Total enthalpy change = -5.645kjmol-1

Answered by  | 9th Mar, 2009, 03:36: PM

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