Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Calculate EMF of the following cell at 298 K             Ni(s) ½ Ni2+(0.01M) ½½ Ag+(0.1M) ½Ag(s)
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Given : E° cell = 1.05V
            For galvanic cell
            Ni(s) + 2Ag+(aq) → Ni2+(aq) + 2Ag(s) ,the Nernst equation is 
           
             E cell = E0 Cell- ( 2.303x RT /nF ) log10 [Ni2+] / [Ag+]2
                        = 1.05 V – (0.059)/ 2 log10 [0.01] / [0.1]2
                        = 1.05 V – 0.0 = 1.05V as log10 10 = 0
Answered by | 04 Jun, 2014, 03:23: PM

Concept Videos

Multiple Choice Questions Practice Test Subjective Questions Webinar Subjective Questions Pre Board Assessment
Answered Unanswered My Questions My Answers
CBSE 12-science - Chemistry
Q. 6. Calculate the emf of the following cell at 298 K Cr(s)/Cr³+ (0.1M)//Fe²+ (0.01M)/Fe(s) [Given: Eºcell = + 0.30 V]
Asked by amankumar2004112 | 04 May, 2022, 01:12: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Please answer this question.
Asked by Balbir | 02 Oct, 2019, 12:29: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
For what concentration of Ag+ will the EMF of te given cell be zero at 25 C .If the concentration of Cu2+ is 0.1 M. EoAg+ = 0.80v and Eo Cu2+ = 0.34 V
Asked by Jsiajaijiaia | 27 Aug, 2019, 12:23: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Please answer. 
Asked by prakriti12oct | 14 Aug, 2019, 12:46: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Electrochemistry What's 'n' in the equation:           E°(cell) = 0.0591/n log Kc  
Asked by rakeshraghav33 | 19 May, 2018, 03:55: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Predict whether the following redox reaction is feasible under the standard conditions or not.              Sn2+(aq) + Cu(s) →   Sn(s) + Cu2+(aq)
Asked by Topperlearning User | 22 Jun, 2016, 02:42: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Zn(s) | Zn2+(0.01M) || Pb2+(1.OM)|Pb(s) Given: Eo Pb2+/Pb = -0.12V and Eo Zn2+/Zn = -0.76V, what is the cell potential of the cell?
Asked by Topperlearning User | 22 Jun, 2016, 02:41: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Calculate the reduction potential for the following half cell reaction at 298 K.             Ag+(aq) + e- →  Ag(s) Given that   (Ag+) = )0.1M and E° = + 0.80V
Asked by Topperlearning User | 22 Jun, 2016, 02:41: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Calculate EMF of the following cell at 298 K             Ni(s) ½ Ni2+(0.01M) ½½ Ag+(0.1M) ½Ag(s)
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Write the Nernst equation and calculate the emf of the following cell at 298 K.Cu (s) | Cu2+ (0.130 M) || Ag+ (1.00M)| Ag (s) Given: EoCu2+/Cu = 0.34V and EoAg+/Ag = +0.80 V.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt