CBSE Class 11-science Answered
The flow of fluid through a pipe of uniform (circular) cross-section is known as HagenPoiseuille flow. The equations governing the HagenPoiseuille flow can be derived directly from the NavierStokes equations in cylindrical coordinates by making the following set of assumptions:
- The flow is steady ( ).
- The radial and swirl components of the fluid velocity are zero ( ).
- The flow is axisymmetric ( ) and fully developed ( ).
Then the second of the three NavierStokes momentum equations and the continuity equation are identically satisfied. The first momentum equation reduces to , i.e., the pressure is a function of the axial coordinate only. The third momentum equation reduces to:
- where is the dynamic viscosity of the fluid.
- The solution is
Since needs to be finite at , . The no slip boundary condition at the pipe wall requires that at (radius of the pipe), which yields
Thus we have finally the following parabolic velocity profile:
The maximum velocity occurs at the pipe centerline ():
The average velocity can be obtained by integrating over the pipe cross section: