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if the momentum of body decreases by 30% its kinetic energy decreased by
Asked by bhargavchary19 | 23 Dec, 2022, 07:33: AM
Momentum p = ( m v )

where m is mass and v is velocity

Kinetic energy E = (1/2) m v2  = (1/2) =
Kinetic energy E =    ........................(1)
if we differentiate above expression, we get

..............................(2)

where change in kinetic energy is given as ΔE and change in momentum is given as Δp

By dividing eqn.(2) by eqn.(1)

(ΔE/E)   = 2 ( Δp / p )

Hence if momentum decreases by 30% , kinetic energy decreases by 60%
Answered by Thiyagarajan K | 23 Dec, 2022, 09:02: AM

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